1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6

hi mohit,

 dis problem is quite simple as u only hav to write each term in the form of difference as for d st term,u write (x-1)-(x-2) in d numerator n simply do it for all d 3 terms n u will get finally 1/(x-4) - 1/(x-1) = 1/6

now it is a simple quadratic n ur ans will be x=7 , x=-2